Is FREE ENERGY possible? We put this infinite energy engine to test. | |
Petrus
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BRIEF
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Anonymous Coward User ID: 80394903 United States 01/21/2022 03:11 AM Report Abusive Post Report Copyright Violation | Sure,but most of the tech has been suppressed. I think ancient civilizations knew how to do from all the needle like things on the roofs of steeples and what we thought were once just plain buildings might have been power plants. I think Tesla figured it out too. |
Anonymous Coward User ID: 80170150 United States 01/21/2022 03:28 AM Report Abusive Post Report Copyright Violation | conservation of energy laws prohibit "free energy" because you can not make or destroy energy. There is however a loophole. Energy = Joules In electrical terms, Watts, does not equal Joules. In fact, the actual equation relating Joules to Watts is: Joules = Watts x Seconds We live in a time where we know that the rate of time is NOT conserved. It is different at dierent altitudes and velocities, it may not be alot, but is shows that nature does not conserve time. Therefore, if there was an invention that was able to produce more Watts out, than Watts in, the load could have a different rate of time... It could be calculated by the equation Watts to Joules equation and setting the in and out Watts x Seconds equal to each other: Watts(in) x Seconds(in) = Watts(out) x Seconds(out) setting it equal to the output seconds gives: [Watts(in) x Seconds(in)] / Watts(out) = Seconds(out) So for 1 second of out observation, the only thing that would dictate the outputs Seconds of the load would be the ratio of the Watts(in)/Watts(out) If there was 2x more Watts on the output, then for every second we measure with a stop watch, the load should only have 1/2 second of time passed... But how do we measure the load's time? We weigh it, because theortically, if a load is at a differnet rate of time, it's weight is proportional to the force of gravity acting upon the object. Force of gravity = g x mass g being the gravitational constant of earth But g has time a component that define it: g = meters / second^2 An estimatation of the gravitational constant of earth is: g = 9.8 m/s^2 So if an object has less rate of time, then whether it is heavier or lighter can be solved by inserting the 0.5 seconds of time per every 1 second we measure for our example. g = meters / (0.5 seconds)^2 9.8 = meter / 0.5^2 or 9.8 x 0.5^2 = 2.45 So g would be: 2.45 m/s^2 relative to the time that we measure. Obviously the number is less and therefore the object would weight 1/4 of the original weight... So you see, it's not "free energy", or "anti gravity", it's a simple calculation the arises when an electrical signal is able to overcome the amount of Watts input and produce more Watts throw a load, like for example a resistor. How do we acheive this? Highly Efficient Multiphase Resonant Circuits. |
LessThanZero
User ID: 79645664 United States 01/21/2022 09:00 PM Report Abusive Post Report Copyright Violation | conservation of energy laws prohibit "free energy" because you can not make or destroy energy. Quoting: Anonymous Coward 80170150 What people fail to take into account though is that 'energy' is infinite. It's like drawing on a water well that goes down to a reservoir of infinite size. You can keep drawing water from the well without any impact on the capacity/reserve of the reservoir of water. Mind you, you can only draw out a finite amount of water because of time being finite and the fact that your bucket is of a finite size. But no matter how much you draw, you're still not violating any law of conservation, because none is being 'created' or 'destroyed'. Truth is seldom welcome INFP :ltz1: |
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